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-4.9x^2+11.2x+1.2=0
a = -4.9; b = 11.2; c = +1.2;
Δ = b2-4ac
Δ = 11.22-4·(-4.9)·1.2
Δ = 148.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11.2)-\sqrt{148.96}}{2*-4.9}=\frac{-11.2-\sqrt{148.96}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11.2)+\sqrt{148.96}}{2*-4.9}=\frac{-11.2+\sqrt{148.96}}{-9.8} $
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